Non-Right Triangles Subjected to Pythagorean Generalization | Steve Wait – July 7, 2023

This is a follow up to the prior post: Visualizing Exponents of Non-integer Pythagorean Generalization

For any triangle ABC where c is the long leg, an exponent exists that will satisfy an+bn=cn. Thus, via exponentiation, non-right triangles are subjected to generalization of the Pythagorean (et al.) Theorem. Normalizing c and mapping non-integer exponents to the rotating complex plane provides visualization. For n from 1 to (degenerate and isosceles respectively) of a given ρ (a:b ratio), all triangles can be simulated. Note that the locus of Pythagoras (n=2) lies in the Rex Rey plane and α represents the angle of the complex plane.

 

amax=ρ[0,1]=ab{a}_{max}=\rho\left[0,1\right]=\frac{{a}}{b}

 

amin=ρρ+1{a}_{min}=\frac{\rho}{\rho+1}

 

b=aρb=\frac{{a}}{\rho}

 

c=an+bnn=1c=\sqrt[{n}]{{a}^n+{b}^n}=1

 

(angle of complex plane) = α=πn2πα=πn-2π

 

C=cos1(c2+a2+b22ab)∠C=\cos^{-1}{\left(\frac{{-{c}}^2+{a}^2+{b}^2}{2ab}\right)}

 

n=q(x)=cos1(c2+a2+b22ab)  f(x)=cos1((ax+bxx2+a2+b2)2ab)n=q\left(x\right)=\cos^{-1}{\left(\frac{{-{c}}^2+{a}^2+{b}^2}{2ab}\right)\ \cap\ f\left(x\right)=\cos^{-1}{\left(\frac{\left({-\sqrt[{x}]{{a}^x+{b}^x}}^2+{a}^2+{b}^2\right)}{2ab}\right)}}

 

To illustrate, I have created a Geogebra animation found here: Non-Right Triangles Subjected to Pythagorean Generalization

 

Screenshot of Geogebra animation for Non-Right Triangles Subjected to Pythagorean Generalization